二‧情報虛實位能差(泡沫)243Please respect copyright.PENANAFE5zgXmbMY
243Please respect copyright.PENANAut53FVqD6j
錯誤情報與真實情報,會在觀測者與被觀測物之間產生能量差,系統中的量子會從高處往低處流動,捕捉其運動軌跡就能推導未知事件。243Please respect copyright.PENANAn1dgR5Vm37
243Please respect copyright.PENANAO46eOX5BqA
例:243Please respect copyright.PENANAD205Cao9K8
封閉的箱子中有一顆蘋果,設總熵為1。243Please respect copyright.PENANAjCtzUyHzs0
觀測者被告知情報:箱子中有一顆蘋果,總熵為1。243Please respect copyright.PENANA3k3T6UiRtS
開啟箱子,兩系統的總熵相等,因果收束前後沒有情報能量流動。243Please respect copyright.PENANAVWLk3JjDGn
243Please respect copyright.PENANAKkxNs3pTPV
封閉的箱子中有一顆蘋果,設總熵為1。243Please respect copyright.PENANAplPTi6XO73
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。243Please respect copyright.PENANA76Ci2lUO2F
開啟箱子,兩系統的總熵差1,因果收束前後有情報能量流動。243Please respect copyright.PENANAhZZbTeNyVL
243Please respect copyright.PENANAlKv3DWb0sF
封閉的箱子中有一顆蘋果,設總熵為1。243Please respect copyright.PENANAryPUr22msK
觀測者被告知情報:箱子中有兩顆蘋果,總熵為2。243Please respect copyright.PENANAqlFPbsFoSe
不開啟箱子,兩系統的總熵差1,此差異持續存在的狀態,專案內稱之為泡沫。243Please respect copyright.PENANAj6iNUN8T7z
243Please respect copyright.PENANAwNSOxhRhBZ
封閉的箱子中有一顆蘋果,設總熵為1。243Please respect copyright.PENANAflEkcp73ys
100名觀測者被告知情報:箱子中有兩顆蘋果,總熵為2*100=200。243Please respect copyright.PENANAplHFwAFQnN
不開啟箱子,兩系統的總熵差199,此差異持續存在的狀態,總共有199顆泡沫。243Please respect copyright.PENANAaZX8zLO0rJ
243Please respect copyright.PENANA0MlMgpT2V3
根據第二定律,宇宙中的情報總熵必定趨向均衡。泡沫產生的混亂必定會分散至其他系統中。比如:多出來的那些「不存在的蘋果」導致價格下跌,果農賺得的能量因而減少。243Please respect copyright.PENANAMsBbRCCpFG
243Please respect copyright.PENANAnAMW8Cj5Hj
定位、統計、歸納,得知所有粒子的運動狀態就能計算出未來的動向。觀察、分析、統整這些資訊,並導入演算機中的工作,本應交由AI電子腦擔任,但原初智叛亂後,現今局勢反對高性能AI生產,最合乎成本效益的解決方案就是人類頭腦。處理如此複雜的系統需要大量樣本,且必定會出現損壞,最好的方式就是使用Q型複製人。243Please respect copyright.PENANAHdTknLvENM
243Please respect copyright.PENANA3umLd2V0LI
(New)243Please respect copyright.PENANABpDDcByV9Z
新展望:加入纏結粒子技術的精準推導法,下述。243Please respect copyright.PENANAZnpRYD9vYB
243Please respect copyright.PENANANa7GBsanrG
arrow_back
拉普拉斯演算機:情報泡沫儲存槽
more_vert
-
info_outline Info
-
toc Table of Contents
-
share Share
-
format_color_text Display Settings
-
exposure_plus_1 Recommend
-
Sponsor
-
report_problem Report
-
account_circle Login
Search stories, writers or societies
Continue ReadingClear All
What Others Are ReadingRefresh
X
Never miss what's happening on Penana!
拉普拉斯演算機:情報泡沫儲存槽
Author:
LiCh 阿立

ISSUE #2
預知未來的方法:因果率演算理論模型(二)
LIKES 0
READS 239
BOOKMARKS 3
campaign
Request update 0
Sponsor
Suggest Edits

Click to load the next chapter
x
will be deducted


Your current coin balance: 0Click to buy coins
A recurring charge will be deducted , unless you decide to cancel. You can cancel your subscription at any time.
You can also pay with credit card
X
After each update request, the author will receive a notification!
smartphone100 → Request update
X
Sponsor again
Click to login
Login first to show your name as a sponsor.
Thank you for supporting the story! :)
Please Login first.
×
Write down what you like about the story
×
Reading Theme:
Font Size:
Line Spacing:
Paragraph Spacing:
Load the next issue automatically
Reset to default
×
People Who Like This